1992-09-17 02:26:53 +00:00
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/* Code for doing intervals.
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Copyright (C) 1991, 1992 Free Software Foundation, Inc.
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This file is part of GNU Emacs.
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GNU Emacs is free software; you can redistribute it and/or modify
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it under the terms of the GNU General Public License as published by
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the Free Software Foundation; either version 1, or (at your option)
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any later version.
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GNU Emacs is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with GNU Emacs; see the file COPYING. If not, write to
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the Free Software Foundation, 675 Mass Ave, Cambridge, MA 02139, USA. */
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/* NOTES:
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Have to ensure that we can't put symbol nil on a plist, or some
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functions may work incorrectly.
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An idea: Have the owner of the tree keep count of splits and/or
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insertion lengths (in intervals), and balance after every N.
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Need to call *_left_hook when buffer is killed.
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Scan for zero-length, or 0-length to see notes about handling
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zero length interval-markers.
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There are comments around about freeing intervals. It might be
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faster to explicitly free them (put them on the free list) than
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to GC them.
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*/
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#include "config.h"
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#include "lisp.h"
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#include "intervals.h"
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#include "buffer.h"
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#include "screen.h"
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/* Factor for weight-balancing interval trees. */
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Lisp_Object interval_balance_threshold;
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/* Utility functions for intervals. */
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/* Create the root interval of some object, a buffer or string. */
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INTERVAL
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create_root_interval (parent)
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Lisp_Object parent;
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{
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INTERVAL new = make_interval ();
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if (XTYPE (parent) == Lisp_Buffer)
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{
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new->total_length = BUF_Z (XBUFFER (parent)) - 1;
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XBUFFER (parent)->intervals = new;
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}
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else if (XTYPE (parent) == Lisp_String)
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{
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new->total_length = XSTRING (parent)->size;
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XSTRING (parent)->intervals = new;
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}
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new->parent = (INTERVAL) parent;
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new->position = 1;
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return new;
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}
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/* Make the interval TARGET have exactly the properties of SOURCE */
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void
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copy_properties (source, target)
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register INTERVAL source, target;
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{
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if (DEFAULT_INTERVAL_P (source) && DEFAULT_INTERVAL_P (target))
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return;
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COPY_INTERVAL_CACHE (source, target);
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target->plist = Fcopy_sequence (source->plist);
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}
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/* Merge the properties of interval SOURCE into the properties
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of interval TARGET. */
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static void
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merge_properties (source, target)
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register INTERVAL source, target;
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{
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register Lisp_Object o, sym, val;
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if (DEFAULT_INTERVAL_P (source) && DEFAULT_INTERVAL_P (target))
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return;
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MERGE_INTERVAL_CACHE (source, target);
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o = source->plist;
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while (! EQ (o, Qnil))
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{
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sym = Fcar (o);
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val = Fmemq (sym, target->plist);
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if (NILP (val))
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{
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o = Fcdr (o);
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val = Fcar (o);
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target->plist = Fcons (sym, Fcons (val, target->plist));
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o = Fcdr (o);
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}
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else
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o = Fcdr (Fcdr (o));
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}
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}
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/* Return 1 if the two intervals have the same properties,
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0 otherwise. */
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int
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intervals_equal (i0, i1)
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INTERVAL i0, i1;
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{
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register Lisp_Object i0_cdr, i0_sym, i1_val;
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register i1_len;
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if (DEFAULT_INTERVAL_P (i0) && DEFAULT_INTERVAL_P (i1))
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return 1;
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i1_len = XFASTINT (Flength (i1->plist));
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if (i1_len & 0x1) /* Paranoia -- plists are always even */
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abort ();
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i1_len /= 2;
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i0_cdr = i0->plist;
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while (!NILP (i0_cdr))
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{
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/* Lengths of the two plists were unequal */
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if (i1_len == 0)
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return 0;
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i0_sym = Fcar (i0_cdr);
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i1_val = Fmemq (i0_sym, i1->plist);
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/* i0 has something i1 doesn't */
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if (EQ (i1_val, Qnil))
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return 0;
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/* i0 and i1 both have sym, but it has different values in each */
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i0_cdr = Fcdr (i0_cdr);
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if (! Fequal (i1_val, Fcar (i0_cdr)))
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return 0;
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i0_cdr = Fcdr (i0_cdr);
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i1_len--;
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}
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/* Lengths of the two plists were unequal */
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if (i1_len > 0)
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return 0;
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return 1;
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}
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static int icount;
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static int idepth;
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static int zero_length;
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static int depth;
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/* Traverse an interval tree TREE, performing FUNCTION on each node.
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Perhaps we should pass the depth as an argument. */
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void
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traverse_intervals (tree, position, function)
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INTERVAL tree;
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int position;
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void (* function) ();
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{
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if (NULL_INTERVAL_P (tree))
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return;
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depth++;
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traverse_intervals (tree->left, position, function);
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position += LEFT_TOTAL_LENGTH (tree);
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tree->position = position;
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(*function) (tree);
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position += LENGTH (tree);
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traverse_intervals (tree->right, position, function);
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depth--;
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}
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#if 0
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/* These functions are temporary, for debugging purposes only. */
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INTERVAL search_interval, found_interval;
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void
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check_for_interval (i)
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register INTERVAL i;
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{
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if (i == search_interval)
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{
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found_interval = i;
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icount++;
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}
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}
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INTERVAL
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search_for_interval (i, tree)
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register INTERVAL i, tree;
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{
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icount = 0;
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search_interval = i;
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found_interval = NULL_INTERVAL;
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traverse_intervals (tree, 1, &check_for_interval);
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return found_interval;
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}
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static void
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inc_interval_count (i)
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INTERVAL i;
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{
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icount++;
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if (LENGTH (i) == 0)
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zero_length++;
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if (depth > idepth)
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idepth = depth;
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}
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int
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count_intervals (i)
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register INTERVAL i;
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{
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icount = 0;
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idepth = 0;
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zero_length = 0;
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traverse_intervals (i, 1, &inc_interval_count);
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return icount;
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}
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static INTERVAL
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root_interval (interval)
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INTERVAL interval;
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{
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register INTERVAL i = interval;
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while (! ROOT_INTERVAL_P (i))
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i = i->parent;
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return i;
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}
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#endif
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/* Assuming that a left child exists, perform the following operation:
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A B
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/ \ / \
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B => A
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/ \ / \
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c c
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*/
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static INTERVAL
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rotate_right (interval)
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INTERVAL interval;
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{
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INTERVAL i;
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INTERVAL B = interval->left;
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int len = LENGTH (interval);
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/* Deal with any Parent of A; make it point to B. */
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if (! ROOT_INTERVAL_P (interval))
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if (AM_LEFT_CHILD (interval))
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interval->parent->left = interval->left;
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else
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interval->parent->right = interval->left;
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interval->left->parent = interval->parent;
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/* B gets the same length as A, since it get A's position in the tree. */
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interval->left->total_length = interval->total_length;
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/* B becomes the parent of A. */
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i = interval->left->right;
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interval->left->right = interval;
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interval->parent = interval->left;
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/* A gets c as left child. */
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interval->left = i;
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if (! NULL_INTERVAL_P (i))
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i->parent = interval;
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interval->total_length = (len + LEFT_TOTAL_LENGTH (interval)
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+ RIGHT_TOTAL_LENGTH (interval));
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return B;
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}
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/* Assuming that a right child exists, perform the following operation:
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A B
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/ \ / \
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B => A
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/ \ / \
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c c
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*/
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static INTERVAL
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rotate_left (interval)
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INTERVAL interval;
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{
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INTERVAL i;
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INTERVAL B = interval->right;
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int len = LENGTH (interval);
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/* Deal with the parent of A. */
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if (! ROOT_INTERVAL_P (interval))
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if (AM_LEFT_CHILD (interval))
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interval->parent->left = interval->right;
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else
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interval->parent->right = interval->right;
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interval->right->parent = interval->parent;
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/* B must have the same total length of A. */
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interval->right->total_length = interval->total_length;
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/* Make B the parent of A */
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i = interval->right->left;
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interval->right->left = interval;
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interval->parent = interval->right;
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/* Make A point to c */
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interval->right = i;
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if (! NULL_INTERVAL_P (i))
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i->parent = interval;
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interval->total_length = (len + LEFT_TOTAL_LENGTH (interval)
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+ RIGHT_TOTAL_LENGTH (interval));
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return B;
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}
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1992-09-19 01:11:21 +00:00
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/* Split INTERVAL into two pieces, starting the second piece at character
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position OFFSET (counting from 1), relative to INTERVAL. The right-hand
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piece (second, lexicographically) is returned.
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The size and position fields of the two intervals are set based upon
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those of the original interval. The property list of the new interval
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is reset, thus it is up to the caller to do the right thing with the
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result.
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1992-09-17 02:26:53 +00:00
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Note that this does not change the position of INTERVAL; if it is a root,
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it is still a root after this operation. */
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INTERVAL
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1992-09-19 01:11:21 +00:00
|
|
|
|
split_interval_right (interval, offset)
|
1992-09-17 02:26:53 +00:00
|
|
|
|
INTERVAL interval;
|
1992-09-19 01:11:21 +00:00
|
|
|
|
int offset;
|
1992-09-17 02:26:53 +00:00
|
|
|
|
{
|
|
|
|
|
INTERVAL new = make_interval ();
|
|
|
|
|
int position = interval->position;
|
1992-09-19 01:11:21 +00:00
|
|
|
|
int new_length = LENGTH (interval) - offset + 1;
|
1992-09-17 02:26:53 +00:00
|
|
|
|
|
1992-09-19 01:11:21 +00:00
|
|
|
|
new->position = position + offset - 1;
|
1992-09-17 02:26:53 +00:00
|
|
|
|
new->parent = interval;
|
|
|
|
|
#if 0
|
|
|
|
|
copy_properties (interval, new);
|
|
|
|
|
#endif
|
|
|
|
|
|
|
|
|
|
if (LEAF_INTERVAL_P (interval) || NULL_RIGHT_CHILD (interval))
|
|
|
|
|
{
|
|
|
|
|
interval->right = new;
|
|
|
|
|
new->total_length = new_length;
|
|
|
|
|
|
|
|
|
|
return new;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Insert the new node between INTERVAL and its right child. */
|
|
|
|
|
new->right = interval->right;
|
|
|
|
|
interval->right->parent = new;
|
|
|
|
|
interval->right = new;
|
|
|
|
|
|
|
|
|
|
new->total_length = new_length + new->right->total_length;
|
|
|
|
|
|
|
|
|
|
return new;
|
|
|
|
|
}
|
|
|
|
|
|
1992-09-19 01:11:21 +00:00
|
|
|
|
/* Split INTERVAL into two pieces, starting the second piece at character
|
|
|
|
|
position OFFSET (counting from 1), relative to INTERVAL. The left-hand
|
|
|
|
|
piece (first, lexicographically) is returned.
|
1992-09-17 02:26:53 +00:00
|
|
|
|
|
1992-09-19 01:11:21 +00:00
|
|
|
|
The size and position fields of the two intervals are set based upon
|
|
|
|
|
those of the original interval. The property list of the new interval
|
|
|
|
|
is reset, thus it is up to the caller to do the right thing with the
|
|
|
|
|
result.
|
|
|
|
|
|
|
|
|
|
Note that this does not change the position of INTERVAL; if it is a root,
|
|
|
|
|
it is still a root after this operation. */
|
1992-09-17 02:26:53 +00:00
|
|
|
|
|
|
|
|
|
INTERVAL
|
1992-09-19 01:11:21 +00:00
|
|
|
|
split_interval_left (interval, offset)
|
1992-09-17 02:26:53 +00:00
|
|
|
|
INTERVAL interval;
|
1992-09-19 01:11:21 +00:00
|
|
|
|
int offset;
|
1992-09-17 02:26:53 +00:00
|
|
|
|
{
|
|
|
|
|
INTERVAL new = make_interval ();
|
|
|
|
|
int position = interval->position;
|
1992-09-19 01:11:21 +00:00
|
|
|
|
int new_length = offset - 1;
|
1992-09-17 02:26:53 +00:00
|
|
|
|
|
|
|
|
|
#if 0
|
|
|
|
|
copy_properties (interval, new);
|
|
|
|
|
#endif
|
|
|
|
|
|
|
|
|
|
new->position = interval->position;
|
|
|
|
|
|
1992-09-19 01:11:21 +00:00
|
|
|
|
interval->position = interval->position + offset - 1;
|
1992-09-17 02:26:53 +00:00
|
|
|
|
new->parent = interval;
|
|
|
|
|
|
|
|
|
|
if (NULL_LEFT_CHILD (interval))
|
|
|
|
|
{
|
|
|
|
|
interval->left = new;
|
|
|
|
|
new->total_length = new_length;
|
|
|
|
|
|
|
|
|
|
return new;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Insert the new node between INTERVAL and its left child. */
|
|
|
|
|
new->left = interval->left;
|
|
|
|
|
new->left->parent = new;
|
|
|
|
|
interval->left = new;
|
|
|
|
|
new->total_length = LENGTH (new) + LEFT_TOTAL_LENGTH (new);
|
|
|
|
|
|
|
|
|
|
return new;
|
|
|
|
|
}
|
|
|
|
|
|
1992-09-19 01:11:21 +00:00
|
|
|
|
/* Find the interval containing text position POSITION in the text
|
|
|
|
|
represented by the interval tree TREE. POSITION is relative to
|
|
|
|
|
the beginning of that text.
|
1992-09-17 02:26:53 +00:00
|
|
|
|
|
1992-09-19 01:11:21 +00:00
|
|
|
|
The `position' field, which is a cache of an interval's position,
|
|
|
|
|
is updated in the interval found. Other functions (e.g., next_interval)
|
|
|
|
|
will update this cache based on the result of find_interval. */
|
|
|
|
|
|
|
|
|
|
INLINE INTERVAL
|
1992-09-17 02:26:53 +00:00
|
|
|
|
find_interval (tree, position)
|
|
|
|
|
register INTERVAL tree;
|
|
|
|
|
register int position;
|
|
|
|
|
{
|
|
|
|
|
register int relative_position = position;
|
|
|
|
|
|
|
|
|
|
if (NULL_INTERVAL_P (tree))
|
|
|
|
|
return NULL_INTERVAL;
|
|
|
|
|
|
|
|
|
|
if (position > TOTAL_LENGTH (tree))
|
|
|
|
|
abort (); /* Paranoia */
|
|
|
|
|
#if 0
|
|
|
|
|
position = TOTAL_LENGTH (tree);
|
|
|
|
|
#endif
|
|
|
|
|
|
|
|
|
|
while (1)
|
|
|
|
|
{
|
|
|
|
|
if (relative_position <= LEFT_TOTAL_LENGTH (tree))
|
|
|
|
|
{
|
|
|
|
|
tree = tree->left;
|
|
|
|
|
}
|
|
|
|
|
else if (relative_position > (TOTAL_LENGTH (tree)
|
|
|
|
|
- RIGHT_TOTAL_LENGTH (tree)))
|
|
|
|
|
{
|
|
|
|
|
relative_position -= (TOTAL_LENGTH (tree)
|
|
|
|
|
- RIGHT_TOTAL_LENGTH (tree));
|
|
|
|
|
tree = tree->right;
|
|
|
|
|
}
|
|
|
|
|
else
|
|
|
|
|
{
|
|
|
|
|
tree->position = LEFT_TOTAL_LENGTH (tree)
|
|
|
|
|
+ position - relative_position + 1;
|
|
|
|
|
return tree;
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Find the succeeding interval (lexicographically) to INTERVAL.
|
1992-09-19 01:11:21 +00:00
|
|
|
|
Sets the `position' field based on that of INTERVAL (see
|
|
|
|
|
find_interval). */
|
1992-09-17 02:26:53 +00:00
|
|
|
|
|
|
|
|
|
INTERVAL
|
|
|
|
|
next_interval (interval)
|
|
|
|
|
register INTERVAL interval;
|
|
|
|
|
{
|
|
|
|
|
register INTERVAL i = interval;
|
|
|
|
|
register int next_position;
|
|
|
|
|
|
|
|
|
|
if (NULL_INTERVAL_P (i))
|
|
|
|
|
return NULL_INTERVAL;
|
|
|
|
|
next_position = interval->position + LENGTH (interval);
|
|
|
|
|
|
|
|
|
|
if (! NULL_RIGHT_CHILD (i))
|
|
|
|
|
{
|
|
|
|
|
i = i->right;
|
|
|
|
|
while (! NULL_LEFT_CHILD (i))
|
|
|
|
|
i = i->left;
|
|
|
|
|
|
|
|
|
|
i->position = next_position;
|
|
|
|
|
return i;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
while (! NULL_PARENT (i))
|
|
|
|
|
{
|
|
|
|
|
if (AM_LEFT_CHILD (i))
|
|
|
|
|
{
|
|
|
|
|
i = i->parent;
|
|
|
|
|
i->position = next_position;
|
|
|
|
|
return i;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
i = i->parent;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
return NULL_INTERVAL;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Find the preceding interval (lexicographically) to INTERVAL.
|
1992-09-19 01:11:21 +00:00
|
|
|
|
Sets the `position' field based on that of INTERVAL (see
|
|
|
|
|
find_interval). */
|
1992-09-17 02:26:53 +00:00
|
|
|
|
|
|
|
|
|
INTERVAL
|
|
|
|
|
previous_interval (interval)
|
|
|
|
|
register INTERVAL interval;
|
|
|
|
|
{
|
|
|
|
|
register INTERVAL i;
|
|
|
|
|
register position_of_previous;
|
|
|
|
|
|
|
|
|
|
if (NULL_INTERVAL_P (interval))
|
|
|
|
|
return NULL_INTERVAL;
|
|
|
|
|
|
|
|
|
|
if (! NULL_LEFT_CHILD (interval))
|
|
|
|
|
{
|
|
|
|
|
i = interval->left;
|
|
|
|
|
while (! NULL_RIGHT_CHILD (i))
|
|
|
|
|
i = i->right;
|
|
|
|
|
|
|
|
|
|
i->position = interval->position - LENGTH (i);
|
|
|
|
|
return i;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
i = interval;
|
|
|
|
|
while (! NULL_PARENT (i))
|
|
|
|
|
{
|
|
|
|
|
if (AM_RIGHT_CHILD (i))
|
|
|
|
|
{
|
|
|
|
|
i = i->parent;
|
|
|
|
|
|
|
|
|
|
i->position = interval->position - LENGTH (i);
|
|
|
|
|
return i;
|
|
|
|
|
}
|
|
|
|
|
i = i->parent;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
return NULL_INTERVAL;
|
|
|
|
|
}
|
|
|
|
|
|
1992-09-19 01:11:21 +00:00
|
|
|
|
#if 0
|
1992-09-17 02:26:53 +00:00
|
|
|
|
/* Traverse a path down the interval tree TREE to the interval
|
|
|
|
|
containing POSITION, adjusting all nodes on the path for
|
|
|
|
|
an addition of LENGTH characters. Insertion between two intervals
|
|
|
|
|
(i.e., point == i->position, where i is second interval) means
|
|
|
|
|
text goes into second interval.
|
|
|
|
|
|
|
|
|
|
Modifications are needed to handle the hungry bits -- after simply
|
|
|
|
|
finding the interval at position (don't add length going down),
|
|
|
|
|
if it's the beginning of the interval, get the previous interval
|
|
|
|
|
and check the hugry bits of both. Then add the length going back up
|
|
|
|
|
to the root. */
|
|
|
|
|
|
|
|
|
|
static INTERVAL
|
|
|
|
|
adjust_intervals_for_insertion (tree, position, length)
|
|
|
|
|
INTERVAL tree;
|
|
|
|
|
int position, length;
|
|
|
|
|
{
|
|
|
|
|
register int relative_position;
|
|
|
|
|
register INTERVAL this;
|
|
|
|
|
|
|
|
|
|
if (TOTAL_LENGTH (tree) == 0) /* Paranoia */
|
|
|
|
|
abort ();
|
|
|
|
|
|
|
|
|
|
/* If inserting at point-max of a buffer, that position
|
|
|
|
|
will be out of range */
|
|
|
|
|
if (position > TOTAL_LENGTH (tree))
|
|
|
|
|
position = TOTAL_LENGTH (tree);
|
|
|
|
|
relative_position = position;
|
|
|
|
|
this = tree;
|
|
|
|
|
|
|
|
|
|
while (1)
|
|
|
|
|
{
|
|
|
|
|
if (relative_position <= LEFT_TOTAL_LENGTH (this))
|
|
|
|
|
{
|
|
|
|
|
this->total_length += length;
|
|
|
|
|
this = this->left;
|
|
|
|
|
}
|
|
|
|
|
else if (relative_position > (TOTAL_LENGTH (this)
|
|
|
|
|
- RIGHT_TOTAL_LENGTH (this)))
|
|
|
|
|
{
|
|
|
|
|
relative_position -= (TOTAL_LENGTH (this)
|
|
|
|
|
- RIGHT_TOTAL_LENGTH (this));
|
|
|
|
|
this->total_length += length;
|
|
|
|
|
this = this->right;
|
|
|
|
|
}
|
|
|
|
|
else
|
|
|
|
|
{
|
|
|
|
|
/* If we are to use zero-length intervals as buffer pointers,
|
|
|
|
|
then this code will have to change. */
|
|
|
|
|
this->total_length += length;
|
|
|
|
|
this->position = LEFT_TOTAL_LENGTH (this)
|
|
|
|
|
+ position - relative_position + 1;
|
|
|
|
|
return tree;
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
}
|
1992-09-19 01:11:21 +00:00
|
|
|
|
#endif
|
|
|
|
|
|
|
|
|
|
/* Effect an adjustment corresponding to the addition of LENGTH characters
|
|
|
|
|
of text. Do this by finding the interval containing POSITION in the
|
|
|
|
|
interval tree TREE, and then adjusting all of it's ancestors by adding
|
|
|
|
|
LENGTH to them.
|
|
|
|
|
|
|
|
|
|
If POSITION is the first character of an interval, meaning that point
|
|
|
|
|
is actually between the two intervals, make the new text belong to
|
|
|
|
|
the interval which is "sticky".
|
|
|
|
|
|
1992-09-21 23:57:58 +00:00
|
|
|
|
If both intervals are "sticky", then make them belong to the left-most
|
1992-09-19 01:11:21 +00:00
|
|
|
|
interval. Another possibility would be to create a new interval for
|
|
|
|
|
this text, and make it have the merged properties of both ends. */
|
|
|
|
|
|
|
|
|
|
static INTERVAL
|
|
|
|
|
adjust_intervals_for_insertion (tree, position, length)
|
|
|
|
|
INTERVAL tree;
|
|
|
|
|
int position, length;
|
|
|
|
|
{
|
|
|
|
|
register INTERVAL i;
|
|
|
|
|
|
|
|
|
|
if (TOTAL_LENGTH (tree) == 0) /* Paranoia */
|
|
|
|
|
abort ();
|
|
|
|
|
|
|
|
|
|
/* If inserting at point-max of a buffer, that position
|
|
|
|
|
will be out of range. */
|
|
|
|
|
if (position > TOTAL_LENGTH (tree))
|
|
|
|
|
position = TOTAL_LENGTH (tree);
|
|
|
|
|
|
|
|
|
|
i = find_interval (tree, position);
|
|
|
|
|
/* If we are positioned between intervals, check the stickiness of
|
|
|
|
|
both of them. */
|
|
|
|
|
if (position == i->position
|
|
|
|
|
&& position != 1)
|
|
|
|
|
{
|
|
|
|
|
register prev = previous_interval (i);
|
|
|
|
|
|
|
|
|
|
/* If both intervals are sticky here, then default to the
|
|
|
|
|
left-most one. But perhaps we should create a new
|
|
|
|
|
interval here instead... */
|
|
|
|
|
if (END_STICKY (prev))
|
|
|
|
|
i = prev;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
while (! NULL_INTERVAL_P (i))
|
|
|
|
|
{
|
|
|
|
|
i->total_length += length;
|
|
|
|
|
i = i->parent
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
return tree;
|
|
|
|
|
}
|
1992-09-17 02:26:53 +00:00
|
|
|
|
|
|
|
|
|
/* Merge interval I with its lexicographic successor. Note that
|
|
|
|
|
this does not deal with the properties, or delete I. */
|
|
|
|
|
|
|
|
|
|
INTERVAL
|
|
|
|
|
merge_interval_right (i)
|
|
|
|
|
register INTERVAL i;
|
|
|
|
|
{
|
|
|
|
|
register int absorb = LENGTH (i);
|
|
|
|
|
|
|
|
|
|
/* Zero out this interval. */
|
|
|
|
|
i->total_length -= absorb;
|
|
|
|
|
|
|
|
|
|
/* Find the succeeding interval. */
|
|
|
|
|
if (! NULL_RIGHT_CHILD (i)) /* It's below us. Add absorb
|
|
|
|
|
as we descend. */
|
|
|
|
|
{
|
|
|
|
|
i = i->right;
|
|
|
|
|
while (! NULL_LEFT_CHILD (i))
|
|
|
|
|
{
|
|
|
|
|
i->total_length += absorb;
|
|
|
|
|
i = i->left;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
i->total_length += absorb;
|
|
|
|
|
return i;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
while (! NULL_PARENT (i)) /* It's above us. Subtract as
|
|
|
|
|
we ascend. */
|
|
|
|
|
{
|
|
|
|
|
if (AM_LEFT_CHILD (i))
|
|
|
|
|
{
|
|
|
|
|
i = i->parent;
|
|
|
|
|
return i;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
i = i->parent;
|
|
|
|
|
i->total_length -= absorb;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
return NULL_INTERVAL;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Merge interval I with its lexicographic predecessor. Note that
|
|
|
|
|
this does not deal with the properties, or delete I.*/
|
|
|
|
|
|
|
|
|
|
INTERVAL
|
|
|
|
|
merge_interval_left (i)
|
|
|
|
|
register INTERVAL i;
|
|
|
|
|
{
|
|
|
|
|
register int absorb = LENGTH (i);
|
|
|
|
|
|
|
|
|
|
/* Zero out this interval. */
|
|
|
|
|
i->total_length -= absorb;
|
|
|
|
|
|
|
|
|
|
/* Find the preceding interval. */
|
|
|
|
|
if (! NULL_LEFT_CHILD (i)) /* It's below us. Go down,
|
|
|
|
|
adding ABSORB as we go. */
|
|
|
|
|
{
|
|
|
|
|
i = i->left;
|
|
|
|
|
while (! NULL_RIGHT_CHILD (i))
|
|
|
|
|
{
|
|
|
|
|
i->total_length += absorb;
|
|
|
|
|
i = i->right;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
i->total_length += absorb;
|
|
|
|
|
return i;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
while (! NULL_PARENT (i)) /* It's above us. Go up,
|
|
|
|
|
subtracting ABSORB. */
|
|
|
|
|
{
|
|
|
|
|
if (AM_RIGHT_CHILD (i))
|
|
|
|
|
{
|
|
|
|
|
i = i->parent;
|
|
|
|
|
return i;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
i = i->parent;
|
|
|
|
|
i->total_length -= absorb;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
return NULL_INTERVAL;
|
|
|
|
|
}
|
|
|
|
|
|
1992-09-19 01:11:21 +00:00
|
|
|
|
/* Delete an node I from its interval tree by merging its subtrees
|
|
|
|
|
into one subtree which is then returned. Caller is responsible for
|
1992-09-17 02:26:53 +00:00
|
|
|
|
storing the resulting subtree into its parent. */
|
|
|
|
|
|
|
|
|
|
static INTERVAL
|
|
|
|
|
delete_node (i)
|
|
|
|
|
register INTERVAL i;
|
|
|
|
|
{
|
|
|
|
|
register INTERVAL migrate, this;
|
|
|
|
|
register int migrate_amt;
|
|
|
|
|
|
|
|
|
|
if (NULL_INTERVAL_P (i->left))
|
|
|
|
|
return i->right;
|
|
|
|
|
if (NULL_INTERVAL_P (i->right))
|
|
|
|
|
return i->left;
|
|
|
|
|
|
|
|
|
|
migrate = i->left;
|
|
|
|
|
migrate_amt = i->left->total_length;
|
|
|
|
|
this = i->right;
|
|
|
|
|
this->total_length += migrate_amt;
|
|
|
|
|
while (! NULL_INTERVAL_P (this->left))
|
|
|
|
|
{
|
|
|
|
|
this = this->left;
|
|
|
|
|
this->total_length += migrate_amt;
|
|
|
|
|
}
|
|
|
|
|
this->left = migrate;
|
|
|
|
|
migrate->parent = this;
|
|
|
|
|
|
|
|
|
|
return i->right;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Delete interval I from its tree by calling `delete_node'
|
|
|
|
|
and properly connecting the resultant subtree.
|
|
|
|
|
|
|
|
|
|
I is presumed to be empty; that is, no adjustments are made
|
|
|
|
|
for the length of I. */
|
|
|
|
|
|
|
|
|
|
void
|
|
|
|
|
delete_interval (i)
|
|
|
|
|
register INTERVAL i;
|
|
|
|
|
{
|
|
|
|
|
register INTERVAL parent;
|
|
|
|
|
int amt = LENGTH (i);
|
|
|
|
|
|
|
|
|
|
if (amt > 0) /* Only used on zero-length intervals now. */
|
|
|
|
|
abort ();
|
|
|
|
|
|
|
|
|
|
if (ROOT_INTERVAL_P (i))
|
|
|
|
|
{
|
|
|
|
|
Lisp_Object owner = (Lisp_Object) i->parent;
|
|
|
|
|
parent = delete_node (i);
|
|
|
|
|
if (! NULL_INTERVAL_P (parent))
|
|
|
|
|
parent->parent = (INTERVAL) owner;
|
|
|
|
|
|
|
|
|
|
if (XTYPE (owner) == Lisp_Buffer)
|
|
|
|
|
XBUFFER (owner)->intervals = parent;
|
|
|
|
|
else if (XTYPE (owner) == Lisp_String)
|
|
|
|
|
XSTRING (owner)->intervals = parent;
|
|
|
|
|
else
|
|
|
|
|
abort ();
|
|
|
|
|
|
|
|
|
|
return;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
parent = i->parent;
|
|
|
|
|
if (AM_LEFT_CHILD (i))
|
|
|
|
|
{
|
|
|
|
|
parent->left = delete_node (i);
|
|
|
|
|
if (! NULL_INTERVAL_P (parent->left))
|
|
|
|
|
parent->left->parent = parent;
|
|
|
|
|
}
|
|
|
|
|
else
|
|
|
|
|
{
|
|
|
|
|
parent->right = delete_node (i);
|
|
|
|
|
if (! NULL_INTERVAL_P (parent->right))
|
|
|
|
|
parent->right->parent = parent;
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
|
1992-09-21 23:57:58 +00:00
|
|
|
|
/* Find the interval in TREE corresponding to the character position FROM
|
|
|
|
|
and delete as much as possible of AMOUNT from that interval, starting
|
|
|
|
|
after the relative position of FROM within it. Return the amount
|
|
|
|
|
actually deleted, and if the interval was zeroed-out, delete that
|
|
|
|
|
interval node from the tree.
|
1992-09-17 02:26:53 +00:00
|
|
|
|
|
1992-09-21 23:57:58 +00:00
|
|
|
|
Do this by recursing down TREE to the interval in question, and
|
|
|
|
|
deleting the appropriate amount of text. */
|
1992-09-17 02:26:53 +00:00
|
|
|
|
|
|
|
|
|
static int
|
|
|
|
|
interval_deletion_adjustment (tree, from, amount)
|
|
|
|
|
register INTERVAL tree;
|
|
|
|
|
register int from, amount;
|
|
|
|
|
{
|
|
|
|
|
register int relative_position = from;
|
|
|
|
|
|
|
|
|
|
if (NULL_INTERVAL_P (tree))
|
|
|
|
|
return 0;
|
|
|
|
|
|
|
|
|
|
/* Left branch */
|
|
|
|
|
if (relative_position <= LEFT_TOTAL_LENGTH (tree))
|
|
|
|
|
{
|
|
|
|
|
int subtract = interval_deletion_adjustment (tree->left,
|
|
|
|
|
relative_position,
|
|
|
|
|
amount);
|
|
|
|
|
tree->total_length -= subtract;
|
|
|
|
|
return subtract;
|
|
|
|
|
}
|
|
|
|
|
/* Right branch */
|
|
|
|
|
else if (relative_position > (TOTAL_LENGTH (tree)
|
|
|
|
|
- RIGHT_TOTAL_LENGTH (tree)))
|
|
|
|
|
{
|
|
|
|
|
int subtract;
|
|
|
|
|
|
|
|
|
|
relative_position -= (tree->total_length
|
|
|
|
|
- RIGHT_TOTAL_LENGTH (tree));
|
|
|
|
|
subtract = interval_deletion_adjustment (tree->right,
|
|
|
|
|
relative_position,
|
|
|
|
|
amount);
|
|
|
|
|
tree->total_length -= subtract;
|
|
|
|
|
return subtract;
|
|
|
|
|
}
|
|
|
|
|
/* Here -- this node */
|
|
|
|
|
else
|
|
|
|
|
{
|
|
|
|
|
/* If this is a zero-length, marker interval, then
|
|
|
|
|
we must skip it. */
|
|
|
|
|
|
|
|
|
|
if (relative_position == LEFT_TOTAL_LENGTH (tree) + 1)
|
|
|
|
|
{
|
|
|
|
|
/* This means we're deleting from the beginning of this interval. */
|
|
|
|
|
register int my_amount = LENGTH (tree);
|
|
|
|
|
|
|
|
|
|
if (amount < my_amount)
|
|
|
|
|
{
|
|
|
|
|
tree->total_length -= amount;
|
|
|
|
|
return amount;
|
|
|
|
|
}
|
|
|
|
|
else
|
|
|
|
|
{
|
|
|
|
|
tree->total_length -= my_amount;
|
|
|
|
|
if (LENGTH (tree) != 0)
|
|
|
|
|
abort (); /* Paranoia */
|
|
|
|
|
|
|
|
|
|
delete_interval (tree);
|
|
|
|
|
return my_amount;
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
else /* Deleting starting in the middle. */
|
|
|
|
|
{
|
|
|
|
|
register int my_amount = ((tree->total_length
|
|
|
|
|
- RIGHT_TOTAL_LENGTH (tree))
|
|
|
|
|
- relative_position + 1);
|
|
|
|
|
|
|
|
|
|
if (amount <= my_amount)
|
|
|
|
|
{
|
|
|
|
|
tree->total_length -= amount;
|
|
|
|
|
return amount;
|
|
|
|
|
}
|
|
|
|
|
else
|
|
|
|
|
{
|
|
|
|
|
tree->total_length -= my_amount;
|
|
|
|
|
return my_amount;
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
|
1992-09-21 23:57:58 +00:00
|
|
|
|
/* Never reach here */
|
1992-09-17 02:26:53 +00:00
|
|
|
|
abort ();
|
|
|
|
|
}
|
|
|
|
|
|
1992-09-21 23:57:58 +00:00
|
|
|
|
/* Effect the adjustments neccessary to the interval tree of BUFFER
|
|
|
|
|
to correspond to the deletion of LENGTH characters from that buffer
|
|
|
|
|
text. The deletion is effected at position START (relative to the
|
|
|
|
|
buffer). */
|
|
|
|
|
|
1992-09-17 02:26:53 +00:00
|
|
|
|
static void
|
|
|
|
|
adjust_intervals_for_deletion (buffer, start, length)
|
|
|
|
|
struct buffer *buffer;
|
|
|
|
|
int start, length;
|
|
|
|
|
{
|
|
|
|
|
register int left_to_delete = length;
|
|
|
|
|
register INTERVAL tree = buffer->intervals;
|
|
|
|
|
register int deleted;
|
|
|
|
|
|
|
|
|
|
if (NULL_INTERVAL_P (tree))
|
|
|
|
|
return;
|
|
|
|
|
|
|
|
|
|
if (length == TOTAL_LENGTH (tree))
|
|
|
|
|
{
|
|
|
|
|
buffer->intervals = NULL_INTERVAL;
|
|
|
|
|
return;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
if (ONLY_INTERVAL_P (tree))
|
|
|
|
|
{
|
|
|
|
|
tree->total_length -= length;
|
|
|
|
|
return;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
if (start > TOTAL_LENGTH (tree))
|
|
|
|
|
start = TOTAL_LENGTH (tree);
|
|
|
|
|
while (left_to_delete > 0)
|
|
|
|
|
{
|
|
|
|
|
left_to_delete -= interval_deletion_adjustment (tree, start,
|
|
|
|
|
left_to_delete);
|
|
|
|
|
tree = buffer->intervals;
|
|
|
|
|
if (left_to_delete == tree->total_length)
|
|
|
|
|
{
|
|
|
|
|
buffer->intervals = NULL_INTERVAL;
|
|
|
|
|
return;
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
|
1992-09-21 23:57:58 +00:00
|
|
|
|
/* Make the adjustments neccessary to the interval tree of BUFFER to
|
|
|
|
|
represent an addition or deletion of LENGTH characters starting
|
|
|
|
|
at position START. Addition or deletion is indicated by the sign
|
|
|
|
|
of LENGTH. */
|
1992-09-17 02:26:53 +00:00
|
|
|
|
|
|
|
|
|
INLINE void
|
|
|
|
|
offset_intervals (buffer, start, length)
|
|
|
|
|
struct buffer *buffer;
|
|
|
|
|
int start, length;
|
|
|
|
|
{
|
|
|
|
|
if (NULL_INTERVAL_P (buffer->intervals) || length == 0)
|
|
|
|
|
return;
|
|
|
|
|
|
|
|
|
|
if (length > 0)
|
|
|
|
|
adjust_intervals_for_insertion (buffer->intervals, start, length);
|
|
|
|
|
else
|
|
|
|
|
adjust_intervals_for_deletion (buffer, start, -length);
|
|
|
|
|
}
|
|
|
|
|
|
1992-09-21 23:57:58 +00:00
|
|
|
|
/* Make an exact copy of interval tree SOURCE which descends from
|
|
|
|
|
PARENT. This is done by recursing through SOURCE, copying
|
|
|
|
|
the current interval and its properties, and then adjusting
|
|
|
|
|
the pointers of the copy. */
|
|
|
|
|
|
1992-09-17 02:26:53 +00:00
|
|
|
|
static INTERVAL
|
|
|
|
|
reproduce_tree (source, parent)
|
|
|
|
|
INTERVAL source, parent;
|
|
|
|
|
{
|
|
|
|
|
register INTERVAL t = make_interval ();
|
|
|
|
|
|
|
|
|
|
bcopy (source, t, INTERVAL_SIZE);
|
|
|
|
|
copy_properties (source, t);
|
|
|
|
|
t->parent = parent;
|
|
|
|
|
if (! NULL_LEFT_CHILD (source))
|
|
|
|
|
t->left = reproduce_tree (source->left, t);
|
|
|
|
|
if (! NULL_RIGHT_CHILD (source))
|
|
|
|
|
t->right = reproduce_tree (source->right, t);
|
|
|
|
|
|
|
|
|
|
return t;
|
|
|
|
|
}
|
|
|
|
|
|
1992-09-21 23:57:58 +00:00
|
|
|
|
/* Make a new interval of length LENGTH starting at START in the
|
|
|
|
|
group of intervals INTERVALS, which is actually an interval tree.
|
|
|
|
|
Returns the new interval.
|
|
|
|
|
|
|
|
|
|
Generate an error if the new positions would overlap an existing
|
|
|
|
|
interval. */
|
|
|
|
|
|
1992-09-17 02:26:53 +00:00
|
|
|
|
static INTERVAL
|
|
|
|
|
make_new_interval (intervals, start, length)
|
|
|
|
|
INTERVAL intervals;
|
|
|
|
|
int start, length;
|
|
|
|
|
{
|
|
|
|
|
INTERVAL slot;
|
|
|
|
|
|
|
|
|
|
slot = find_interval (intervals, start);
|
|
|
|
|
if (start + length > slot->position + LENGTH (slot))
|
|
|
|
|
error ("Interval would overlap");
|
|
|
|
|
|
|
|
|
|
if (start == slot->position && length == LENGTH (slot))
|
|
|
|
|
return slot;
|
|
|
|
|
|
|
|
|
|
if (slot->position == start)
|
|
|
|
|
{
|
|
|
|
|
/* New right node. */
|
|
|
|
|
split_interval_right (slot, length + 1);
|
|
|
|
|
return slot;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
if (slot->position + LENGTH (slot) == start + length)
|
|
|
|
|
{
|
|
|
|
|
/* New left node. */
|
|
|
|
|
split_interval_left (slot, LENGTH (slot) - length + 1);
|
|
|
|
|
return slot;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Convert interval SLOT into three intervals. */
|
|
|
|
|
split_interval_left (slot, start - slot->position + 1);
|
|
|
|
|
split_interval_right (slot, length + 1);
|
|
|
|
|
return slot;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
void
|
|
|
|
|
map_intervals (source, destination, position)
|
|
|
|
|
INTERVAL source, destination;
|
|
|
|
|
int position;
|
|
|
|
|
{
|
|
|
|
|
register INTERVAL i, t;
|
|
|
|
|
|
|
|
|
|
if (NULL_INTERVAL_P (source))
|
|
|
|
|
return;
|
|
|
|
|
i = find_interval (destination, position);
|
|
|
|
|
if (NULL_INTERVAL_P (i))
|
|
|
|
|
return;
|
|
|
|
|
|
|
|
|
|
t = find_interval (source, 1);
|
|
|
|
|
while (! NULL_INTERVAL_P (t))
|
|
|
|
|
{
|
|
|
|
|
i = make_new_interval (destination, position, LENGTH (t));
|
|
|
|
|
position += LENGTH (t);
|
|
|
|
|
copy_properties (t, i);
|
|
|
|
|
t = next_interval (t);
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Insert the intervals of NEW_TREE into BUFFER at POSITION.
|
|
|
|
|
|
|
|
|
|
This is used in insdel.c when inserting Lisp_Strings into
|
|
|
|
|
the buffer. The text corresponding to NEW_TREE is already in
|
|
|
|
|
the buffer when this is called. The intervals of new tree are
|
|
|
|
|
those belonging to the string being inserted; a copy is not made.
|
|
|
|
|
|
|
|
|
|
If the inserted text had no intervals associated, this function
|
|
|
|
|
simply returns -- offset_intervals should handle placing the
|
1992-09-19 01:11:21 +00:00
|
|
|
|
text in the correct interval, depending on the sticky bits.
|
1992-09-17 02:26:53 +00:00
|
|
|
|
|
|
|
|
|
If the inserted text had properties (intervals), then there are two
|
|
|
|
|
cases -- either insertion happened in the middle of some interval,
|
|
|
|
|
or between two intervals.
|
|
|
|
|
|
|
|
|
|
If the text goes into the middle of an interval, then new
|
|
|
|
|
intervals are created in the middle with only the properties of
|
|
|
|
|
the new text, *unless* the macro MERGE_INSERTIONS is true, in
|
|
|
|
|
which case the new text has the union of its properties and those
|
|
|
|
|
of the text into which it was inserted.
|
|
|
|
|
|
|
|
|
|
If the text goes between two intervals, then if neither interval
|
1992-09-19 01:11:21 +00:00
|
|
|
|
had its appropriate sticky property set (front_sticky, rear_sticky),
|
|
|
|
|
the new text has only its properties. If one of the sticky properties
|
1992-09-17 02:26:53 +00:00
|
|
|
|
is set, then the new text "sticks" to that region and its properties
|
|
|
|
|
depend on merging as above. If both the preceding and succeding
|
1992-09-19 01:11:21 +00:00
|
|
|
|
intervals to the new text are "sticky", then the new text retains
|
|
|
|
|
only its properties, as if neither sticky property were set. Perhaps
|
1992-09-17 02:26:53 +00:00
|
|
|
|
we should consider merging all three sets of properties onto the new
|
|
|
|
|
text... */
|
|
|
|
|
|
|
|
|
|
void
|
|
|
|
|
graft_intervals_into_buffer (new_tree, position, b)
|
|
|
|
|
INTERVAL new_tree;
|
|
|
|
|
int position;
|
|
|
|
|
struct buffer *b;
|
|
|
|
|
{
|
|
|
|
|
register INTERVAL under, over, this;
|
|
|
|
|
register INTERVAL tree = b->intervals;
|
|
|
|
|
|
|
|
|
|
/* If the new text has no properties, it becomes part of whatever
|
|
|
|
|
interval it was inserted into. */
|
|
|
|
|
if (NULL_INTERVAL_P (new_tree))
|
|
|
|
|
return;
|
|
|
|
|
|
|
|
|
|
/* Paranoia -- the text has already been added, so this buffer
|
|
|
|
|
should be of non-zero length. */
|
|
|
|
|
if (TOTAL_LENGTH (tree) == 0)
|
|
|
|
|
abort ();
|
|
|
|
|
|
|
|
|
|
if (NULL_INTERVAL_P (tree))
|
|
|
|
|
{
|
|
|
|
|
/* The inserted text constitutes the whole buffer, so
|
|
|
|
|
simply copy over the interval structure. */
|
|
|
|
|
if (BUF_Z (b) == TOTAL_LENGTH (new_tree))
|
|
|
|
|
{
|
|
|
|
|
b->intervals = reproduce_tree (new_tree, tree->parent);
|
|
|
|
|
/* Explicitly free the old tree here. */
|
|
|
|
|
|
|
|
|
|
return;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Create an interval tree in which to place a copy
|
|
|
|
|
of the intervals of the inserted string. */
|
|
|
|
|
{
|
|
|
|
|
Lisp_Object buffer;
|
|
|
|
|
XSET (buffer, Lisp_Buffer, b);
|
|
|
|
|
create_root_interval (buffer);
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
else
|
|
|
|
|
if (TOTAL_LENGTH (tree) == TOTAL_LENGTH (new_tree))
|
|
|
|
|
|
|
|
|
|
/* If the buffer contains only the new string, but
|
|
|
|
|
there was already some interval tree there, then it may be
|
|
|
|
|
some zero length intervals. Eventually, do something clever
|
|
|
|
|
about inserting properly. For now, just waste the old intervals. */
|
|
|
|
|
{
|
|
|
|
|
b->intervals = reproduce_tree (new_tree, tree->parent);
|
|
|
|
|
/* Explicitly free the old tree here. */
|
|
|
|
|
|
|
|
|
|
return;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
this = under = find_interval (tree, position);
|
|
|
|
|
if (NULL_INTERVAL_P (under)) /* Paranoia */
|
|
|
|
|
abort ();
|
|
|
|
|
over = find_interval (new_tree, 1);
|
|
|
|
|
|
|
|
|
|
/* Insertion between intervals */
|
|
|
|
|
if (position == under->position)
|
|
|
|
|
{
|
|
|
|
|
/* First interval -- none precede it. */
|
|
|
|
|
if (position == 1)
|
|
|
|
|
{
|
1992-09-19 01:11:21 +00:00
|
|
|
|
if (! FRONT_STICKY (under))
|
1992-09-17 02:26:53 +00:00
|
|
|
|
/* The inserted string keeps its own properties. */
|
|
|
|
|
while (! NULL_INTERVAL_P (over))
|
|
|
|
|
{
|
|
|
|
|
position = LENGTH (over) + 1;
|
|
|
|
|
this = split_interval_left (this, position);
|
|
|
|
|
copy_properties (over, this);
|
|
|
|
|
over = next_interval (over);
|
|
|
|
|
}
|
|
|
|
|
else
|
|
|
|
|
/* This string sticks to under */
|
|
|
|
|
while (! NULL_INTERVAL_P (over))
|
|
|
|
|
{
|
|
|
|
|
position = LENGTH (over) + 1;
|
|
|
|
|
this = split_interval_left (this, position);
|
|
|
|
|
copy_properties (under, this);
|
|
|
|
|
if (MERGE_INSERTIONS (under))
|
|
|
|
|
merge_properties (over, this);
|
|
|
|
|
over = next_interval (over);
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
else
|
|
|
|
|
{
|
|
|
|
|
INTERVAL prev = previous_interval (under);
|
|
|
|
|
if (NULL_INTERVAL_P (prev))
|
|
|
|
|
abort ();
|
|
|
|
|
|
1992-09-19 01:11:21 +00:00
|
|
|
|
if (END_STICKY (prev))
|
1992-09-17 02:26:53 +00:00
|
|
|
|
{
|
1992-09-19 01:11:21 +00:00
|
|
|
|
if (FRONT_STICKY (under))
|
|
|
|
|
/* The intervals go inbetween as the two sticky
|
1992-09-17 02:26:53 +00:00
|
|
|
|
properties cancel each other. Should we change
|
|
|
|
|
this policy? */
|
|
|
|
|
while (! NULL_INTERVAL_P (over))
|
|
|
|
|
{
|
|
|
|
|
position = LENGTH (over) + 1;
|
|
|
|
|
this = split_interval_left (this, position);
|
|
|
|
|
copy_properties (over, this);
|
|
|
|
|
over = next_interval (over);
|
|
|
|
|
}
|
|
|
|
|
else
|
|
|
|
|
/* The intervals stick to prev */
|
|
|
|
|
while (! NULL_INTERVAL_P (over))
|
|
|
|
|
{
|
|
|
|
|
position = LENGTH (over) + 1;
|
|
|
|
|
this = split_interval_left (this, position);
|
|
|
|
|
copy_properties (prev, this);
|
|
|
|
|
if (MERGE_INSERTIONS (prev))
|
|
|
|
|
merge_properties (over, this);
|
|
|
|
|
over = next_interval (over);
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
else
|
|
|
|
|
{
|
1992-09-19 01:11:21 +00:00
|
|
|
|
if (FRONT_STICKY (under))
|
1992-09-17 02:26:53 +00:00
|
|
|
|
/* The intervals stick to under */
|
|
|
|
|
while (! NULL_INTERVAL_P (over))
|
|
|
|
|
{
|
|
|
|
|
position = LENGTH (over) + 1;
|
|
|
|
|
this = split_interval_left (this, position);
|
|
|
|
|
copy_properties (under, this);
|
|
|
|
|
if (MERGE_INSERTIONS (under))
|
|
|
|
|
merge_properties (over, this);
|
|
|
|
|
over = next_interval (over);
|
|
|
|
|
}
|
|
|
|
|
else
|
|
|
|
|
/* The intervals go inbetween */
|
|
|
|
|
while (! NULL_INTERVAL_P (over))
|
|
|
|
|
{
|
|
|
|
|
position = LENGTH (over) + 1;
|
|
|
|
|
this = split_interval_left (this, position);
|
|
|
|
|
copy_properties (over, this);
|
|
|
|
|
over = next_interval (over);
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
b->intervals = balance_intervals (b->intervals);
|
|
|
|
|
return;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Here for insertion in the middle of an interval. */
|
|
|
|
|
|
|
|
|
|
if (TOTAL_LENGTH (new_tree) < LENGTH (this))
|
|
|
|
|
{
|
|
|
|
|
INTERVAL end_unchanged
|
|
|
|
|
= split_interval_right (this, TOTAL_LENGTH (new_tree) + 1);
|
|
|
|
|
copy_properties (under, end_unchanged);
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
position = position - tree->position + 1;
|
|
|
|
|
while (! NULL_INTERVAL_P (over))
|
|
|
|
|
{
|
|
|
|
|
this = split_interval_right (under, position);
|
|
|
|
|
copy_properties (over, this);
|
|
|
|
|
if (MERGE_INSERTIONS (under))
|
|
|
|
|
merge_properties (under, this);
|
|
|
|
|
|
|
|
|
|
position = LENGTH (over) + 1;
|
|
|
|
|
over = next_interval (over);
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
b->intervals = balance_intervals (b->intervals);
|
|
|
|
|
return;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Intervals can have properties which are hooks to call. Look for
|
|
|
|
|
the property HOOK on interval I, and if found, call its value as
|
|
|
|
|
a function.*/
|
|
|
|
|
|
|
|
|
|
void
|
|
|
|
|
run_hooks (i, hook)
|
|
|
|
|
INTERVAL i;
|
|
|
|
|
Lisp_Object hook;
|
|
|
|
|
{
|
|
|
|
|
register Lisp_Object tail = i->plist;
|
|
|
|
|
register Lisp_Object sym, val;
|
|
|
|
|
|
|
|
|
|
while (! NILP (tail))
|
|
|
|
|
{
|
|
|
|
|
sym = Fcar (tail);
|
|
|
|
|
if (EQ (sym, hook))
|
|
|
|
|
{
|
|
|
|
|
Lisp_Object begin, end;
|
|
|
|
|
XFASTINT (begin) = i->position;
|
|
|
|
|
XFASTINT (end) = i->position + LENGTH (i) - 1;
|
|
|
|
|
val = Fcar (Fcdr (tail));
|
|
|
|
|
call2 (val, begin, end);
|
|
|
|
|
return;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
tail = Fcdr (Fcdr (tail));
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Set point in BUFFER to POSITION. If the target position is in
|
|
|
|
|
an invisible interval which is not displayed with a special glyph,
|
|
|
|
|
skip intervals until we find one. Point may be at the first
|
|
|
|
|
position of an invisible interval, if it is displayed with a
|
|
|
|
|
special glyph.
|
|
|
|
|
|
|
|
|
|
This is the only place `PT' is an lvalue in all of emacs. */
|
|
|
|
|
|
|
|
|
|
void
|
|
|
|
|
set_point (position, buffer)
|
|
|
|
|
register int position;
|
|
|
|
|
register struct buffer *buffer;
|
|
|
|
|
{
|
|
|
|
|
register INTERVAL to, from, target;
|
|
|
|
|
register int iposition = position;
|
|
|
|
|
int buffer_point;
|
|
|
|
|
register Lisp_Object obj;
|
|
|
|
|
int backwards = (position < BUF_PT (buffer)) ? 1 : 0;
|
|
|
|
|
|
|
|
|
|
if (position == buffer->text.pt)
|
|
|
|
|
return;
|
|
|
|
|
|
|
|
|
|
if (NULL_INTERVAL_P (buffer->intervals))
|
|
|
|
|
{
|
|
|
|
|
buffer->text.pt = position;
|
|
|
|
|
return;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Perhaps we should just change `position' to the limit. */
|
|
|
|
|
if (position > BUF_Z (buffer) || position < BUF_BEG (buffer))
|
|
|
|
|
abort ();
|
|
|
|
|
|
|
|
|
|
/* Position Z is really one past the last char in the buffer. */
|
|
|
|
|
if (position == BUF_Z (buffer))
|
|
|
|
|
iposition = position - 1;
|
|
|
|
|
|
|
|
|
|
to = find_interval (buffer->intervals, iposition);
|
|
|
|
|
buffer_point =(BUF_PT (buffer) == BUF_Z (buffer)
|
|
|
|
|
? BUF_Z (buffer) - 1
|
|
|
|
|
: BUF_PT (buffer));
|
|
|
|
|
from = find_interval (buffer->intervals, buffer_point);
|
|
|
|
|
if (NULL_INTERVAL_P (to) || NULL_INTERVAL_P (from))
|
|
|
|
|
abort (); /* Paranoia */
|
|
|
|
|
|
|
|
|
|
/* Moving within an interval */
|
|
|
|
|
if (to == from && INTERVAL_VISIBLE_P (to))
|
|
|
|
|
{
|
|
|
|
|
buffer->text.pt = position;
|
|
|
|
|
return;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Here for the case of moving into another interval. */
|
|
|
|
|
|
|
|
|
|
target = to;
|
|
|
|
|
while (! INTERVAL_VISIBLE_P (to) && ! DISPLAY_INVISIBLE_GLYPH (to)
|
|
|
|
|
&& ! NULL_INTERVAL_P (to))
|
|
|
|
|
to = (backwards ? previous_interval (to) : next_interval (to));
|
|
|
|
|
if (NULL_INTERVAL_P (to))
|
|
|
|
|
return;
|
|
|
|
|
|
|
|
|
|
/* Here we know we are actually moving to another interval. */
|
|
|
|
|
if (INTERVAL_VISIBLE_P (to))
|
|
|
|
|
{
|
|
|
|
|
/* If we skipped some intervals, go to the closest point
|
|
|
|
|
in the interval we've stopped at. */
|
|
|
|
|
if (to != target)
|
|
|
|
|
buffer->text.pt = (backwards
|
|
|
|
|
? to->position + LENGTH (to) - 1
|
|
|
|
|
: to->position);
|
|
|
|
|
else
|
|
|
|
|
buffer->text.pt = position;
|
|
|
|
|
}
|
|
|
|
|
else
|
|
|
|
|
buffer->text.pt = to->position;
|
|
|
|
|
|
|
|
|
|
/* We should run point-left and point-entered hooks here, iff the
|
|
|
|
|
two intervals are not equivalent. */
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Check for read-only intervals. Call the modification hooks if any.
|
|
|
|
|
Check for the range START up to (but not including) TO.
|
|
|
|
|
|
|
|
|
|
First all intervals of the region are checked that they are
|
|
|
|
|
modifiable, then all the modification hooks are called in
|
|
|
|
|
lexicographic order. */
|
|
|
|
|
|
|
|
|
|
void
|
|
|
|
|
verify_interval_modification (buf, start, end)
|
|
|
|
|
struct buffer *buf;
|
|
|
|
|
int start, end;
|
|
|
|
|
{
|
|
|
|
|
register INTERVAL intervals = buf->intervals;
|
|
|
|
|
register INTERVAL i;
|
|
|
|
|
register Lisp_Object hooks = Qnil;
|
|
|
|
|
|
|
|
|
|
if (NULL_INTERVAL_P (intervals))
|
|
|
|
|
return;
|
|
|
|
|
|
|
|
|
|
if (start > end)
|
|
|
|
|
{
|
|
|
|
|
int temp = start;
|
|
|
|
|
start = end;
|
|
|
|
|
end = temp;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
if (start == BUF_Z (buf))
|
|
|
|
|
{
|
|
|
|
|
if (BUF_Z (buf) == 1)
|
|
|
|
|
abort ();
|
|
|
|
|
|
|
|
|
|
i = find_interval (intervals, start - 1);
|
1992-09-19 01:11:21 +00:00
|
|
|
|
if (! END_STICKY_P (i))
|
1992-09-17 02:26:53 +00:00
|
|
|
|
return;
|
|
|
|
|
}
|
|
|
|
|
else
|
|
|
|
|
i = find_interval (intervals, start);
|
|
|
|
|
|
|
|
|
|
do
|
|
|
|
|
{
|
|
|
|
|
register Lisp_Object mod_hook;
|
|
|
|
|
if (! INTERVAL_WRITABLE_P (i))
|
|
|
|
|
error ("Attempt to write in a protected interval");
|
|
|
|
|
mod_hook = Fget (Qmodification, i->plist);
|
|
|
|
|
if (! EQ (mod_hook, Qnil))
|
|
|
|
|
hooks = Fcons (mod_hook, hooks);
|
|
|
|
|
i = next_interval (i);
|
|
|
|
|
}
|
|
|
|
|
while (! NULL_INTERVAL_P (i) && i->position <= end);
|
|
|
|
|
|
|
|
|
|
hooks = Fnreverse (hooks);
|
|
|
|
|
while (! EQ (hooks, Qnil))
|
|
|
|
|
call2 (Fcar (hooks), i->position, i->position + LENGTH (i) - 1);
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Balance an interval node if the amount of text in its left and right
|
|
|
|
|
subtrees differs by more than the percentage specified by
|
|
|
|
|
`interval-balance-threshold'. */
|
|
|
|
|
|
|
|
|
|
static INTERVAL
|
|
|
|
|
balance_an_interval (i)
|
|
|
|
|
INTERVAL i;
|
|
|
|
|
{
|
|
|
|
|
register int total_children_size = (LEFT_TOTAL_LENGTH (i)
|
|
|
|
|
+ RIGHT_TOTAL_LENGTH (i));
|
|
|
|
|
register int threshold = (XFASTINT (interval_balance_threshold)
|
|
|
|
|
* (total_children_size / 100));
|
|
|
|
|
|
|
|
|
|
if (LEFT_TOTAL_LENGTH (i) > RIGHT_TOTAL_LENGTH (i)
|
|
|
|
|
&& (LEFT_TOTAL_LENGTH (i) - RIGHT_TOTAL_LENGTH (i)) > threshold)
|
|
|
|
|
return rotate_right (i);
|
|
|
|
|
|
|
|
|
|
if (LEFT_TOTAL_LENGTH (i) > RIGHT_TOTAL_LENGTH (i)
|
|
|
|
|
&& (LEFT_TOTAL_LENGTH (i) - RIGHT_TOTAL_LENGTH (i)) > threshold)
|
|
|
|
|
return rotate_right (i);
|
|
|
|
|
|
|
|
|
|
#if 0
|
|
|
|
|
if (LEFT_TOTAL_LENGTH (i) >
|
|
|
|
|
(RIGHT_TOTAL_LENGTH (i) + XINT (interval_balance_threshold)))
|
|
|
|
|
return rotate_right (i);
|
|
|
|
|
|
|
|
|
|
if (RIGHT_TOTAL_LENGTH (i) >
|
|
|
|
|
(LEFT_TOTAL_LENGTH (i) + XINT (interval_balance_threshold)))
|
|
|
|
|
return rotate_left (i);
|
|
|
|
|
#endif
|
|
|
|
|
|
|
|
|
|
return i;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Balance the interval tree TREE. Balancing is by weight
|
|
|
|
|
(the amount of text). */
|
|
|
|
|
|
|
|
|
|
INTERVAL
|
|
|
|
|
balance_intervals (tree)
|
|
|
|
|
register INTERVAL tree;
|
|
|
|
|
{
|
|
|
|
|
register INTERVAL new_tree;
|
|
|
|
|
|
|
|
|
|
if (NULL_INTERVAL_P (tree))
|
|
|
|
|
return NULL_INTERVAL;
|
|
|
|
|
|
|
|
|
|
new_tree = tree;
|
|
|
|
|
do
|
|
|
|
|
{
|
|
|
|
|
tree = new_tree;
|
|
|
|
|
new_tree = balance_an_interval (new_tree);
|
|
|
|
|
}
|
|
|
|
|
while (new_tree != tree);
|
|
|
|
|
|
|
|
|
|
return new_tree;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Produce an interval tree reflecting the interval structure in
|
|
|
|
|
TREE from START to START + LENGTH. */
|
|
|
|
|
|
|
|
|
|
static INTERVAL
|
|
|
|
|
copy_intervals (tree, start, length)
|
|
|
|
|
INTERVAL tree;
|
|
|
|
|
int start, length;
|
|
|
|
|
{
|
|
|
|
|
register INTERVAL i, new, t;
|
|
|
|
|
register int got;
|
|
|
|
|
|
|
|
|
|
if (NULL_INTERVAL_P (tree) || length <= 0)
|
|
|
|
|
return NULL_INTERVAL;
|
|
|
|
|
|
|
|
|
|
i = find_interval (tree, start);
|
|
|
|
|
if (NULL_INTERVAL_P (i) || LENGTH (i) == 0)
|
|
|
|
|
abort ();
|
|
|
|
|
|
|
|
|
|
/* If there is only one interval and it's the default, return nil. */
|
|
|
|
|
if ((start - i->position + 1 + length) < LENGTH (i)
|
|
|
|
|
&& DEFAULT_INTERVAL_P (i))
|
|
|
|
|
return NULL_INTERVAL;
|
|
|
|
|
|
|
|
|
|
new = make_interval ();
|
|
|
|
|
new->position = 1;
|
|
|
|
|
got = (LENGTH (i) - (start - i->position));
|
|
|
|
|
new->total_length = got;
|
|
|
|
|
copy_properties (i, new);
|
|
|
|
|
|
|
|
|
|
t = new;
|
|
|
|
|
while (got < length)
|
|
|
|
|
{
|
|
|
|
|
i = next_interval (i);
|
|
|
|
|
t->right = make_interval ();
|
|
|
|
|
t->right->parent = t;
|
|
|
|
|
t->right->position = t->position + got - 1;
|
|
|
|
|
|
|
|
|
|
t = t->right;
|
|
|
|
|
t->total_length = length - got;
|
|
|
|
|
copy_properties (i, t);
|
|
|
|
|
got += LENGTH (i);
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
if (got > length)
|
|
|
|
|
t->total_length -= (got - length);
|
|
|
|
|
|
|
|
|
|
return balance_intervals (new);
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Give buffer SINK the properties of buffer SOURCE from POSITION
|
|
|
|
|
to END. The properties are attached to SINK starting at position AT.
|
|
|
|
|
|
|
|
|
|
No range checking is done. */
|
|
|
|
|
|
|
|
|
|
void
|
|
|
|
|
insert_interval_copy (source, position, end, sink, at)
|
|
|
|
|
struct buffer *source, *sink;
|
|
|
|
|
register int position, end, at;
|
|
|
|
|
{
|
|
|
|
|
INTERVAL interval_copy = copy_intervals (source->intervals,
|
|
|
|
|
position, end - position);
|
|
|
|
|
graft_intervals_into_buffer (interval_copy, at, sink);
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Give STRING the properties of BUFFER from POSITION to LENGTH. */
|
|
|
|
|
|
|
|
|
|
void
|
|
|
|
|
copy_intervals_to_string (string, buffer, position, length)
|
|
|
|
|
Lisp_Object string, buffer;
|
|
|
|
|
int position, length;
|
|
|
|
|
{
|
|
|
|
|
INTERVAL interval_copy = copy_intervals (XBUFFER (buffer)->intervals,
|
|
|
|
|
position, length);
|
|
|
|
|
if (NULL_INTERVAL_P (interval_copy))
|
|
|
|
|
return;
|
|
|
|
|
|
|
|
|
|
interval_copy->parent = (INTERVAL) string;
|
|
|
|
|
XSTRING (string)->intervals = interval_copy;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
INTERVAL
|
|
|
|
|
make_string_interval (string, start, length)
|
|
|
|
|
struct Lisp_String *string;
|
|
|
|
|
int start, length;
|
|
|
|
|
{
|
|
|
|
|
if (start < 1 || start > string->size)
|
|
|
|
|
error ("Interval index out of range");
|
|
|
|
|
if (length < 1 || length > string->size - start + 1)
|
|
|
|
|
error ("Interval won't fit");
|
|
|
|
|
|
|
|
|
|
if (length == 0)
|
|
|
|
|
return NULL_INTERVAL;
|
|
|
|
|
|
|
|
|
|
return make_new_interval (string->intervals, start, length);
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
/* Create an interval of length LENGTH in buffer BUF at position START. */
|
|
|
|
|
|
|
|
|
|
INTERVAL
|
|
|
|
|
make_buffer_interval (buf, start, length)
|
|
|
|
|
struct buffer *buf;
|
|
|
|
|
int start, length;
|
|
|
|
|
{
|
|
|
|
|
if (start < BUF_BEG (buf) || start > BUF_Z (buf))
|
|
|
|
|
error ("Interval index out of range");
|
|
|
|
|
if (length < 1 || length > BUF_Z (buf) - start)
|
|
|
|
|
error ("Interval won't fit");
|
|
|
|
|
|
|
|
|
|
if (length == 0)
|
|
|
|
|
return NULL_INTERVAL;
|
|
|
|
|
|
|
|
|
|
return make_new_interval (buf->intervals, start, length);
|
|
|
|
|
}
|