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Don't duplicate most recent logs. Fix bug in dates after Feb 29 in leap year.

This commit is contained in:
Paul Eggert 1992-04-01 08:57:55 +00:00
parent 906ad89def
commit 23a227f717

View File

@ -2,7 +2,7 @@
# RCS to ChangeLog generator
# $Id: rcs2clog,v 1.3 1992/02/05 17:25:10 eggert Exp eggert $
# $Id: rcs2log,v 1.4 1992/03/21 05:58:05 eggert Exp eggert $
# Generate a change log prefix from RCS/* and the existing ChangeLog (if any).
# Output the new prefix to standard output.
@ -32,15 +32,23 @@ done
# Log into $rlogout the revisions checked in since the first ChangeLog entry.
datearg=-d'>1970'
date=1970
if test -s ChangeLog
then
e='s/^\(...\) \(...\) \(..\) \(..:..:..\) \(....\) .*/\1 \2 \3 \4 \5/p; 1q'
date=`sed -n "$e" <ChangeLog` || exit
case $date in
?*) datearg="-d>$date"
# Add 1 to seconds to avoid duplicating most recent log.
# It's a good thing `rlog' doesn't mind a time ending in `:60'.
e='
/^... ... [ 0-9][0-9] [ 0-9][0-9]:[0-9][0-9]:[0-9][0-9] [0-9]+ /{
printf "%s%.2d %s\n", substr($0,1,17), substr($0,18,2)+1, $5
exit
}
'
d=`awk "$e" <ChangeLog` || exit
case $d in
?*) date=$d
esac
fi
datearg="-d>$date"
rlogout=/tmp/chg$$
trap exit 1 2 13 15
@ -153,7 +161,7 @@ awk <$rlogout '
# and each line of the log is terminated by \r instead of \n.
# Sort the log entries, first by date (in reverse order),
# then by author, then by log entry, and finally by file name (just in case).
sort +1 -2r +3 +0 |
sort +1 -3r +3 +0 |
# Finally, reformat the sorted log entries.
awk '
@ -208,6 +216,7 @@ awk '
# and use it to decide whether to output a blank line.
newclumpname = ""
sep = "\n"
if (date == "") sep = ""
if (newlog ~ /^{[^ }]+}[ ]/) {
i = index(newlog, "}")
newclumpname = substr(newlog, 1, i)
@ -235,13 +244,13 @@ awk '
# into ugly ctime date like "Fri Jan 3 00:03:44 1992".
# Calculate day of week from Gregorian calendar.
i = index($2, "/")
year = substr($2, 1, i-1)
year = substr($2, 1, i-1) + 0
monthday = substr($2, i+1)
i = index(monthday, "/")
month = substr(monthday, 1, i-1)
day = substr(monthday, i+1)
month = substr(monthday, 1, i-1) + 0
day = substr(monthday, i+1) + 0
leap = 0
if (2 <= month && year%4 == 0 && (year%100 != 0 || year%400 == 0)) leap = 1
if (2 < month && year%4 == 0 && (year%100 != 0 || year%400 == 0)) leap = 1
days_since_Sunday_before_epoch = EPOCH_WEEKDAY + year * 365 + int((year + 3) / 4) - int((year + 99) / 100) + int((year + 399) / 400) + mo[month-1] + leap + day - 1
# Print "date fullname (email address)" if the fullname is known;