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Code Issues Releases Activity

; Fix more trivial typos

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This commit is contained in:
Stefan Kangas 2020-09-21 15:41:43 +02:00
parent 611b85b663
commit ebad35e4d9
6 changed files with 6 additions and 6 deletions
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2
test/ChangeLog.1
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@ -1754,7 +1754,7 @@
* indent/prolog.prolog: Test alignment of ->; with operator at bol.
* indent/css-mode.css (.x2): Test alignement inside braces.
* indent/css-mode.css (.x2): Test alignment inside braces.
2013-10-26 Dmitry Gutov <dgutov@yandex.ru>

2
test/lisp/emacs-lisp/faceup-resources/files/test1.txt.faceup
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@ -1,7 +1,7 @@
This is a test of `faceup', a regression test system for font-lock
keywords. It should use major mode `faceup-test-mode'.
«(help-echo):"Baloon tip: Fly smoothly!":«w:WARNING»»: The first word on this line should use
«(help-echo):"Balloon tip: Fly smoothly!":«w:WARNING»»: The first word on this line should use
`font-lock-warning-face', and a tooltip should be displayed if the
mouse pointer is moved over it.

2
test/lisp/files-tests.el
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@ -1406,7 +1406,7 @@ The door of all subtleties!
")
(ert-deftest files-tests-revert-buffer ()
"Test that revert-buffer is succesful."
"Test that revert-buffer is successful."
(files-tests--with-temp-file temp-file-name
(with-temp-buffer
(insert files-tests-lao)

2
test/lisp/net/dbus-tests.el
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@ -322,7 +322,7 @@
(dbus-check-arguments
:session dbus--test-service
'(:array (:dict-entry :string "string" :boolean t))))
;; The second element is `nil' (implicitely). FIXME: Is this right?
;; The second element is `nil' (implicitly). FIXME: Is this right?
(should
(dbus-check-arguments
:session dbus--test-service '(:array (:dict-entry :string "string"))))

2
test/manual/etags/y-src/parse.y
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@ -556,7 +556,7 @@ yylex FUN0()
}
#ifdef TEST
if(nn==n_usr_funs) {
io_error_msg("Couln't turn fp into a ##");
io_error_msg("Couldn't turn fp into a ##");
parse_error=BAD_FUNC;
return ERROR;
}

2
test/manual/indent/ruby.rb
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@ -34,7 +34,7 @@ def foo
# Regexp after whitelisted method.
"abc".sub /b/, 'd'
# Don't mis-match "sub" at the end of words.
# Don't mismatch "sub" at the end of words.
a = asub / aslb + bsub / bslb;
# Highlight the regexp after "if".