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251 lines
9.3 KiB
EmacsLisp
251 lines
9.3 KiB
EmacsLisp
;;; radix-tree.el --- A simple library of radix trees -*- lexical-binding: t; -*-
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;; Copyright (C) 2016-2020 Free Software Foundation, Inc.
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;; Author: Stefan Monnier <monnier@iro.umontreal.ca>
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;; Keywords:
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;; This file is part of GNU Emacs.
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;; GNU Emacs is free software: you can redistribute it and/or modify
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;; it under the terms of the GNU General Public License as published by
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;; the Free Software Foundation, either version 3 of the License, or
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;; (at your option) any later version.
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;; GNU Emacs is distributed in the hope that it will be useful,
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;; but WITHOUT ANY WARRANTY; without even the implied warranty of
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;; MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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;; GNU General Public License for more details.
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;; You should have received a copy of the GNU General Public License
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;; along with GNU Emacs. If not, see <https://www.gnu.org/licenses/>.
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;;; Commentary:
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;; There are many different options for how to represent radix trees
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;; in Elisp. Here I chose a very simple one. A radix-tree can be either:
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;; - a node, of the form ((PREFIX . PTREE) . RTREE) where PREFIX is a string
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;; meaning that everything that starts with PREFIX is in PTREE,
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;; and everything else in RTREE. It also has the property that
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;; everything that starts with the first letter of PREFIX but not with
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;; that whole PREFIX is not in RTREE (i.e. is not in the tree at all).
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;; - anything else is taken as the value to associate with the empty string.
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;; So every node is basically an (improper) alist where each mapping applies
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;; to a different leading letter.
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;;
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;; The main downside of this representation is that the lookup operation
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;; is slower because each level of the tree is an alist rather than some kind
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;; of array, so every level's lookup is O(N) rather than O(1). We could easily
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;; solve this by using char-tables instead of alists, but that would make every
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;; level take up a lot more memory, and it would make the resulting
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;; data structure harder to read (by a human) when printed out.
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;;; Code:
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(defun radix-tree--insert (tree key val i)
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(pcase tree
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(`((,prefix . ,ptree) . ,rtree)
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(let* ((ni (+ i (length prefix)))
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(cmp (compare-strings prefix nil nil key i ni)))
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(if (eq t cmp)
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(let ((nptree (radix-tree--insert ptree key val ni)))
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`((,prefix . ,nptree) . ,rtree))
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(let ((n (if (< cmp 0) (- -1 cmp) (- cmp 1))))
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(if (zerop n)
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(let ((nrtree (radix-tree--insert rtree key val i)))
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`((,prefix . ,ptree) . ,nrtree))
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(let* ((nprefix (substring prefix 0 n))
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(kprefix (substring key (+ i n)))
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(pprefix (substring prefix n))
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(ktree (if (equal kprefix "") val
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`((,kprefix . ,val)))))
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`((,nprefix
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. ((,pprefix . ,ptree) . ,ktree))
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. ,rtree)))))))
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(_
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(if (= (length key) i) val
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(let ((prefix (substring key i)))
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`((,prefix . ,val) . ,tree))))))
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(defun radix-tree--remove (tree key i)
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(pcase tree
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(`((,prefix . ,ptree) . ,rtree)
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(let* ((ni (+ i (length prefix)))
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(cmp (compare-strings prefix nil nil key i ni)))
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(if (eq t cmp)
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(pcase (radix-tree--remove ptree key ni)
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('nil rtree)
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(`((,pprefix . ,pptree))
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`((,(concat prefix pprefix) . ,pptree) . ,rtree))
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(nptree `((,prefix . ,nptree) . ,rtree)))
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(let ((n (if (< cmp 0) (- -1 cmp) (- cmp 1))))
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(if (zerop n)
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(let ((nrtree (radix-tree--remove rtree key i)))
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`((,prefix . ,ptree) . ,nrtree))
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tree)))))
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(_
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(if (= (length key) i) nil tree))))
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(defun radix-tree--lookup (tree string i)
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(pcase tree
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(`((,prefix . ,ptree) . ,rtree)
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(let* ((ni (+ i (length prefix)))
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(cmp (compare-strings prefix nil nil string i ni)))
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(if (eq t cmp)
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(radix-tree--lookup ptree string ni)
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(let ((n (if (< cmp 0) (- -1 cmp) (- cmp 1))))
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(if (zerop n)
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(radix-tree--lookup rtree string i)
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(+ i n))))))
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(val
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(if (and val (equal (length string) i))
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(if (integerp val) `(t . ,val) val)
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i))))
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;; (defun radix-tree--trim (tree string i)
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;; (if (= i (length string))
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;; tree
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;; (pcase tree
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;; (`((,prefix . ,ptree) . ,rtree)
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;; (let* ((ni (+ i (length prefix)))
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;; (cmp (compare-strings prefix nil nil string i ni))
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;; ;; FIXME: We could compute nrtree more efficiently
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;; ;; whenever cmp is not -1 or 1.
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;; (nrtree (radix-tree--trim rtree string i)))
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;; (if (eq t cmp)
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;; (pcase (radix-tree--trim ptree string ni)
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;; (`nil nrtree)
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;; (`((,pprefix . ,pptree))
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;; `((,(concat prefix pprefix) . ,pptree) . ,nrtree))
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;; (nptree `((,prefix . ,nptree) . ,nrtree)))
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;; (let ((n (if (< cmp 0) (- -1 cmp) (- cmp 1))))
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;; (cond
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;; ((equal (+ n i) (length string))
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;; `((,prefix . ,ptree) . ,nrtree))
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;; (t nrtree))))))
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;; (val val))))
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(defun radix-tree--prefixes (tree string i prefixes)
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(pcase tree
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(`((,prefix . ,ptree) . ,rtree)
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(let* ((ni (+ i (length prefix)))
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(cmp (compare-strings prefix nil nil string i ni))
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;; FIXME: We could compute prefixes more efficiently
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;; whenever cmp is not -1 or 1.
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(prefixes (radix-tree--prefixes rtree string i prefixes)))
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(if (eq t cmp)
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(radix-tree--prefixes ptree string ni prefixes)
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prefixes)))
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(val
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(if (null val)
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prefixes
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(cons (cons (substring string 0 i)
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(if (eq (car-safe val) t) (cdr val) val))
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prefixes)))))
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(defun radix-tree--subtree (tree string i)
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(if (equal (length string) i) tree
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(pcase tree
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(`((,prefix . ,ptree) . ,rtree)
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(let* ((ni (+ i (length prefix)))
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(cmp (compare-strings prefix nil nil string i ni)))
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(if (eq t cmp)
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(radix-tree--subtree ptree string ni)
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(let ((n (if (< cmp 0) (- -1 cmp) (- cmp 1))))
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(cond
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((zerop n) (radix-tree--subtree rtree string i))
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((equal (+ n i) (length string))
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(let ((nprefix (substring prefix n)))
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`((,nprefix . ,ptree))))
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(t nil))))))
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(_ nil))))
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;;; Entry points
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(defconst radix-tree-empty nil
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"The empty radix-tree.")
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(defun radix-tree-insert (tree key val)
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"Insert a mapping from KEY to VAL in radix TREE."
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(when (consp val) (setq val `(t . ,val)))
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(if val (radix-tree--insert tree key val 0)
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(radix-tree--remove tree key 0)))
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(defun radix-tree-lookup (tree key)
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"Return the value associated to KEY in radix TREE.
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If not found, return nil."
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(pcase (radix-tree--lookup tree key 0)
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(`(t . ,val) val)
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((pred numberp) nil)
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(val val)))
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(defun radix-tree-subtree (tree string)
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"Return the subtree of TREE rooted at the prefix STRING."
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(radix-tree--subtree tree string 0))
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;; (defun radix-tree-trim (tree string)
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;; "Return a TREE which only holds entries \"related\" to STRING.
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;; \"Related\" is here defined as entries where there's a `string-prefix-p' relation
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;; between STRING and the key."
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;; (radix-tree-trim tree string 0))
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(defun radix-tree-prefixes (tree string)
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"Return an alist of all bindings in TREE for prefixes of STRING."
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(radix-tree--prefixes tree string 0 nil))
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(eval-and-compile
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(pcase-defmacro radix-tree-leaf (vpat)
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"Pattern which matches a radix-tree leaf.
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The pattern VPAT is matched against the leaf's carried value."
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;; FIXME: We'd like to use a negative pattern (not consp), but pcase
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;; doesn't support it. Using `atom' works but generates sub-optimal code.
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`(or `(t . ,,vpat) (and (pred atom) ,vpat))))
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(defun radix-tree-iter-subtrees (tree fun)
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"Apply FUN to every immediate subtree of radix TREE.
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FUN is called with two arguments: PREFIX and SUBTREE.
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You can test if SUBTREE is a leaf (and extract its value) with the
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pcase pattern (radix-tree-leaf PAT)."
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(while tree
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(pcase tree
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(`((,prefix . ,ptree) . ,rtree)
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(funcall fun prefix ptree)
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(setq tree rtree))
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(_ (funcall fun "" tree)
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(setq tree nil)))))
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(defun radix-tree-iter-mappings (tree fun &optional prefix)
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"Apply FUN to every mapping in TREE.
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FUN is called with two arguments: KEY and VAL.
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PREFIX is only used internally."
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(radix-tree-iter-subtrees
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tree
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(lambda (p s)
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(let ((nprefix (concat prefix p)))
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(pcase s
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((radix-tree-leaf v) (funcall fun nprefix v))
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(_ (radix-tree-iter-mappings s fun nprefix)))))))
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;; (defun radix-tree->alist (tree)
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;; (let ((al nil))
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;; (radix-tree-iter-mappings tree (lambda (p v) (push (cons p v) al)))
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;; al))
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(defun radix-tree-count (tree)
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(let ((i 0))
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(radix-tree-iter-mappings tree (lambda (_k _v) (setq i (1+ i))))
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i))
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(declare-function map-apply "map" (function map))
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(defun radix-tree-from-map (map)
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;; Aka (cl-defmethod map-into (map (type (eql radix-tree)))) ...)
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(require 'map)
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(let ((rt nil))
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(map-apply (lambda (k v) (setq rt (radix-tree-insert rt k v))) map)
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rt))
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(provide 'radix-tree)
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;;; radix-tree.el ends here
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