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Fix assertion, &uc->uc_busy is never zero, the intent is to test the

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uc_busy value, and not its address [1].

Remove the single use of the macro, write KASSERT() explicitely in the
code of umtxq_sleep_pi().

Submitted by:	Eric van Gyzen <eric@vangyzen.net> [1]
MFC after:	1 week
This commit is contained in:
Konstantin Belousov 2014-11-13 18:51:09 +00:00
parent 50d75c5b57
commit 416be7a1c6
Notes: svn2git 2020-12-20 02:59:44 +00:00 
svn path=/head/; revision=274478
1 changed files with 1 additions and 2 deletions
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3
sys/kern/kern_umtx.c
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@ -169,7 +169,6 @@ struct umtxq_chain {
};
#define UMTXQ_LOCKED_ASSERT(uc) mtx_assert(&(uc)->uc_lock, MA_OWNED)
#define UMTXQ_BUSY_ASSERT(uc) KASSERT(&(uc)->uc_busy, ("umtx chain is not busy"))
/*
* Don't propagate time-sharing priority, there is a security reason,
@ -1478,7 +1477,7 @@ umtxq_sleep_pi(struct umtx_q *uq, struct umtx_pi *pi,
KASSERT(td == curthread, ("inconsistent uq_thread"));
uc = umtxq_getchain(&uq->uq_key);
UMTXQ_LOCKED_ASSERT(uc);
UMTXQ_BUSY_ASSERT(uc);
KASSERT(uc->uc_busy != 0, ("umtx chain is not busy"));
umtxq_insert(uq);
mtx_lock_spin(&umtx_lock);
if (pi->pi_owner == NULL) {