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330 lines
10 KiB
C
330 lines
10 KiB
C
/*-
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* Copyright (c) 2009 Xin LI <delphij@FreeBSD.org>
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* All rights reserved.
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*
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* Redistribution and use in source and binary forms, with or without
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* modification, are permitted provided that the following conditions
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* are met:
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* 1. Redistributions of source code must retain the above copyright
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* notice, this list of conditions and the following disclaimer.
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* 2. Redistributions in binary form must reproduce the above copyright
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* notice, this list of conditions and the following disclaimer in the
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* documentation and/or other materials provided with the distribution.
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*
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* THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS'' AND
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* ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
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* IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
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* ARE DISCLAIMED. IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
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* FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
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* DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
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* OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
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* HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
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* LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
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* OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
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* SUCH DAMAGE.
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*
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* $FreeBSD$
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*/
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/* This file is #included by gzip.c */
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/*
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* pack(1) file format:
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*
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* The first 7 bytes is the header:
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* 00, 01 - Signature (US, RS), we already validated it earlier.
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* 02..05 - Uncompressed size
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* 06 - Level for the huffman tree (<=24)
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*
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* pack(1) will then store symbols (leaf) nodes count in each huffman
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* tree levels, each level would consume 1 byte (See [1]).
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*
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* After the symbol count table, there is the symbol table, storing
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* symbols represented by corresponding leaf node. EOB is not being
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* explicitly transmitted (not necessary anyway) in the symbol table.
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*
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* Compressed data goes after the symbol table.
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*
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* NOTES
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*
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* [1] If we count EOB into the symbols, that would mean that we will
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* have at most 256 symbols in the huffman tree. pack(1) rejects empty
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* file and files that just repeats one character, which means that we
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* will have at least 2 symbols. Therefore, pack(1) would reduce the
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* last level symbol count by 2 which makes it a number in
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* range [0..254], so all levels' symbol count would fit into 1 byte.
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*/
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#define PACK_HEADER_LENGTH 7
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#define HTREE_MAXLEVEL 24
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/*
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* unpack descriptor
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*
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* Represent the huffman tree in a similar way that pack(1) would
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* store in a packed file. We store all symbols in a linear table,
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* and store pointers to each level's first symbol. In addition to
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* that, maintain two counts for each level: inner nodes count and
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* leaf nodes count.
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*/
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typedef struct {
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int symbol_size; /* Size of the symbol table */
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int treelevels; /* Levels for the huffman tree */
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int *symbolsin; /* Table of leaf symbols count in
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each level */
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int *inodesin; /* Table of internal nodes count in
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each level */
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char *symbol; /* The symbol table */
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char *symbol_eob; /* Pointer to the EOB symbol */
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char **tree; /* Decoding huffman tree (pointers to
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first symbol of each tree level */
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off_t uncompressed_size; /* Uncompressed size */
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FILE *fpIn; /* Input stream */
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FILE *fpOut; /* Output stream */
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} unpack_descriptor_t;
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/*
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* Release resource allocated to an unpack descriptor.
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*
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* Caller is responsible to make sure that all of these pointers are
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* initialized (in our case, they all point to valid memory block).
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* We don't zero out pointers here because nobody else would ever
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* reference the memory block without scrubbing them.
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*/
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static void
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unpack_descriptor_fini(unpack_descriptor_t *unpackd)
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{
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free(unpackd->symbolsin);
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free(unpackd->inodesin);
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free(unpackd->symbol);
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free(unpackd->tree);
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fclose(unpackd->fpIn);
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fclose(unpackd->fpOut);
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}
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/*
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* Recursively fill the internal node count table
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*/
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static void
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unpackd_fill_inodesin(const unpack_descriptor_t *unpackd, int level)
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{
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/*
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* The internal nodes would be 1/2 of total internal nodes and
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* leaf nodes in the next level. For the last level there
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* would be no internal node by definition.
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*/
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if (level < unpackd->treelevels) {
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unpackd_fill_inodesin(unpackd, level + 1);
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unpackd->inodesin[level] = (unpackd->inodesin[level + 1] +
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unpackd->symbolsin[level + 1]) / 2;
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} else
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unpackd->inodesin[level] = 0;
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}
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/*
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* Update counter for accepted bytes
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*/
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static void
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accepted_bytes(off_t *bytes_in, off_t newbytes)
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{
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if (bytes_in != NULL)
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(*bytes_in) += newbytes;
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}
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/*
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* Read file header and construct the tree. Also, prepare the buffered I/O
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* for decode routine.
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*
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* Return value is uncompressed size.
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*/
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static void
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unpack_parse_header(int in, int out, char *pre, size_t prelen, off_t *bytes_in,
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unpack_descriptor_t *unpackd)
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{
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unsigned char hdr[PACK_HEADER_LENGTH]; /* buffer for header */
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ssize_t bytesread; /* Bytes read from the file */
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int i, j, thisbyte;
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/* Prepend the header buffer if we already read some data */
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if (prelen != 0)
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memcpy(hdr, pre, prelen);
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/* Read in and fill the rest bytes of header */
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bytesread = read(in, hdr + prelen, PACK_HEADER_LENGTH - prelen);
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if (bytesread < 0)
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maybe_err("Error reading pack header");
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accepted_bytes(bytes_in, PACK_HEADER_LENGTH);
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/* Obtain uncompressed length (bytes 2,3,4,5)*/
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unpackd->uncompressed_size = 0;
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for (i = 2; i <= 5; i++) {
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unpackd->uncompressed_size <<= 8;
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unpackd->uncompressed_size |= hdr[i];
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}
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/* Get the levels of the tree */
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unpackd->treelevels = hdr[6];
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if (unpackd->treelevels > HTREE_MAXLEVEL || unpackd->treelevels < 1)
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maybe_errx("Huffman tree has insane levels");
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/* Let libc take care for buffering from now on */
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if ((unpackd->fpIn = fdopen(in, "r")) == NULL)
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maybe_err("Can not fdopen() input stream");
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if ((unpackd->fpOut = fdopen(out, "w")) == NULL)
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maybe_err("Can not fdopen() output stream");
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/* Allocate for the tables of bounds and the tree itself */
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unpackd->inodesin =
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calloc(unpackd->treelevels, sizeof(*(unpackd->inodesin)));
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unpackd->symbolsin =
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calloc(unpackd->treelevels, sizeof(*(unpackd->symbolsin)));
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unpackd->tree =
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calloc(unpackd->treelevels, (sizeof (*(unpackd->tree))));
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if (unpackd->inodesin == NULL || unpackd->symbolsin == NULL ||
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unpackd->tree == NULL)
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maybe_err("calloc");
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/* We count from 0 so adjust to match array upper bound */
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unpackd->treelevels--;
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/* Read the levels symbol count table and calculate total */
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unpackd->symbol_size = 1; /* EOB */
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for (i = 0; i <= unpackd->treelevels; i++) {
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if ((thisbyte = fgetc(unpackd->fpIn)) == EOF)
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maybe_err("File appears to be truncated");
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unpackd->symbolsin[i] = (unsigned char)thisbyte;
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unpackd->symbol_size += unpackd->symbolsin[i];
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}
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accepted_bytes(bytes_in, unpackd->treelevels);
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if (unpackd->symbol_size > 256)
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maybe_errx("Bad symbol table");
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/* Allocate for the symbol table, point symbol_eob at the beginning */
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unpackd->symbol_eob = unpackd->symbol = calloc(1, unpackd->symbol_size);
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if (unpackd->symbol == NULL)
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maybe_err("calloc");
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/*
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* Read in the symbol table, which contain [2, 256] symbols.
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* In order to fit the count in one byte, pack(1) would offset
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* it by reducing 2 from the actual number from the last level.
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*
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* We adjust the last level's symbol count by 1 here, because
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* the EOB symbol is not being transmitted explicitly. Another
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* adjustment would be done later afterward.
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*/
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unpackd->symbolsin[unpackd->treelevels]++;
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for (i = 0; i <= unpackd->treelevels; i++) {
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unpackd->tree[i] = unpackd->symbol_eob;
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for (j = 0; j < unpackd->symbolsin[i]; j++) {
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if ((thisbyte = fgetc(unpackd->fpIn)) == EOF)
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maybe_errx("Symbol table truncated");
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*unpackd->symbol_eob++ = (char)thisbyte;
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}
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accepted_bytes(bytes_in, unpackd->symbolsin[i]);
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}
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/* Now, take account for the EOB symbol as well */
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unpackd->symbolsin[unpackd->treelevels]++;
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/*
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* The symbolsin table has been constructed now.
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* Calculate the internal nodes count table based on it.
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*/
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unpackd_fill_inodesin(unpackd, 0);
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}
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/*
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* Decode huffman stream, based on the huffman tree.
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*/
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static void
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unpack_decode(const unpack_descriptor_t *unpackd, off_t *bytes_in)
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{
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int thislevel, thiscode, thisbyte, inlevelindex;
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int i;
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off_t bytes_out = 0;
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const char *thissymbol; /* The symbol pointer decoded from stream */
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/*
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* Decode huffman. Fetch every bytes from the file, get it
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* into 'thiscode' bit-by-bit, then output the symbol we got
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* when one has been found.
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*
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* Assumption: sizeof(int) > ((max tree levels + 1) / 8).
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* bad things could happen if not.
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*/
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thislevel = 0;
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thiscode = thisbyte = 0;
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while ((thisbyte = fgetc(unpackd->fpIn)) != EOF) {
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accepted_bytes(bytes_in, 1);
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/*
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* Split one bit from thisbyte, from highest to lowest,
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* feed the bit into thiscode, until we got a symbol from
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* the tree.
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*/
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for (i = 7; i >= 0; i--) {
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thiscode = (thiscode << 1) | ((thisbyte >> i) & 1);
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/* Did we got a symbol? (referencing leaf node) */
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if (thiscode >= unpackd->inodesin[thislevel]) {
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inlevelindex =
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thiscode - unpackd->inodesin[thislevel];
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if (inlevelindex > unpackd->symbolsin[thislevel])
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maybe_errx("File corrupt");
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thissymbol =
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&(unpackd->tree[thislevel][inlevelindex]);
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if ((thissymbol == unpackd->symbol_eob) &&
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(bytes_out == unpackd->uncompressed_size))
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goto finished;
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fputc((*thissymbol), unpackd->fpOut);
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bytes_out++;
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/* Prepare for next input */
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thislevel = 0; thiscode = 0;
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} else {
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thislevel++;
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if (thislevel > unpackd->treelevels)
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maybe_errx("File corrupt");
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}
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}
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}
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finished:
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if (bytes_out != unpackd->uncompressed_size)
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maybe_errx("Premature EOF");
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}
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/* Handler for pack(1)'ed file */
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static off_t
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unpack(int in, int out, char *pre, size_t prelen, off_t *bytes_in)
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{
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unpack_descriptor_t unpackd;
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in = dup(in);
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if (in == -1)
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maybe_err("dup");
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out = dup(out);
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if (out == -1)
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maybe_err("dup");
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unpack_parse_header(in, out, pre, prelen, bytes_in, &unpackd);
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unpack_decode(&unpackd, bytes_in);
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unpack_descriptor_fini(&unpackd);
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/* If we reached here, the unpack was successful */
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return (unpackd.uncompressed_size);
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}
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